Question

in fig (ii) given below, angle p = 3y find the values of x and y​

Answer 1

Answer:

100-60=x(exterior angle property)

x=40

in triangle pqr

40+y+p+60=180

y+3y=80

y=20

Answer 2

60⁰ + x = 100⁰ (Exterior angle property)

x = 100⁰ - 60⁰

x = 40⁰

100⁰ + y + p = 180⁰ ( Angle sum property)

y + 3y = 180⁰ - 100⁰

4y = 80⁰

y = 20⁰

The values of x is 40⁰ and y is 20⁰.

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