Question

In fig. OA=OB and OD=OC show that tri.AOD=~∆BOC and AD||BC​

Answer 1

⊕ANSWER⊕

In ∆OAD and ∆OBC

OA=OB {given}

OD = OC { given }

angle AOD = angle BOC { vertically oppositie angles }

∆AOD=~∆BOC { SAS }

angle OBC = angle OAD {C.P.C.T.}

for that ADllBC