Question

In figure 3.50, if segment PR ~ seg PQ, show that seg PS > PQ​

Answer 1

Answer:

please figure attaché

Step-by-step explanation:

attachment of figure is needed I will answer it

Answer 2

Step-by-step explanation:

In △PRS, ∠PRS is an obtuse angle.

Since, a traingle can have maximum one obtuse angle.

Hence, ∠PRS is the greatest angle.

Therefore, the side opposite to ∠PRS i.e., PS is the longest side.

Now, seg PS > seg PR > seg RS

∴ seg PS > seg PQ [∵seg PR≅seg PQ]