Question

In figure 3.51, in ΔABC, seg AD and seg BE are altitudes and AE = BD. Prove that segAD≅seg BE

Answer 1

Here Is the answer in the image.

Answer 2

Answer:

Proved

AD ≅ BE

ΔABD ≅ ΔABE

Step-by-step explanation:

in ΔABD

AB² = AD² + BD²  ( Using Pythagoras theorem)

in ΔABE

AB² = AE² + BE²

Equating AB² from both

AD² + BD² = AE² + BE²

AE = BD given

=> AE² = BD²

=> AD² = BE²

=> AD = BE

AD ≅ BE

ΔABD ≅ ΔABE ( as all sides are equal)