Question

In figure 3.85, ꯳ABCD is a parallelogram. It circumscribes the circle with cnetre T. Point E, F, G, H are touching points. If AE=4.5,EB = 5.5, find AD.

Answer 1

Hi ,

We know that the parallelogram circumscribing a

circle is a Rhombus .

ABCD is a parallelogram circumscribing

a circle with center T .

AE = 4.5 ,

EB = 5.5 ( Given )

Therefore , ABCD is a Rhombus .

AB = BC = CD = DA

AD = AB

= AE + EB

= 4.5 + 5.5

= 10

I HOPE THIS HELPS YOU.

: )

Answer 2

Answer:

seg AD =10 Units

Step-by-step explanation:

I Hope you Understand the this solution