Question

In figure AB is parallel to CD and EF is parallel to GH find the value of X,Y,Z and T

Answer 1

Answer:

BUT WHERE IS THE FIGURE

Answer 2

Answer:

Step-by-step explanation:

Given GH || IZ

∠1 = 108°

∠2 = 123°

∠1 + ∠KGH = 180 [linear pair]

108° + ∠KGH = 1

108° + ∠KGH – 108° = 180° – 108°

∠KGH = 72°

∠KGH = x° (corresponding angles if KG is a transversal)

∴ x° = 72°

Similarly

∠2 + ∠GHK = 180° (∵ linear pair)

123° + ∠GHK = 180°

123° + ∠GHK – 123° = 180° – 123°

∠GHK = 57°

Again ∠GHK = y° (corresponding angles if KH is a transversal)

y = 57°

x° +y° + z° = 180° (sum of three angles of a triangle is 180°)

72° + 57° + z° = 180°

129° + z° = 180°

129° + z° – 129° = 180° – 129°

z = 51°

x = 72°,

y = 57°,

z = 51°