Question

in figure AB parallel to CD then the value of x is​

Answer 1

Answer:

From the figure we have, ∠EPB=180° −(5x−20°) .......(1)

[ Since ∠BPE+∠QPB=180°]

Again ∠PQD=∠QPB [ Similar angles]

or, 180°−(5x−20°)=2x−10°

or, 7x=210°

or,x=219°/7=30°

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