Question

in figure abcd is a rectangle.find the value of x and y,where ab=30 cm,bc=x-y,cd=x+y,ad+14 cm

Answer 1

hope it's helpful......

Answer 2

Answer:

x = 22 and y = 8

Step-by-step explanation:

Refer the attached image .

AB=30 cm

BC=(x-y)

CD=(x+y)

AD =14 cm

Since ABCD is rectangle so by property of rectangle

AB = CD

$30=x+y$  --1

AD =BC

$14=x-y$  --2

Adding 1 and 2

$30+14=x+y+x-y$

$44=2x$

$\frac{44}{2}=x$

$22=x$

Substituting the value of x in 1 we get the value of y

$30=22+y$

$30-22=y$

$8=y$

Thus x = 22 and y = 8