Question

in figure AP B and a qtr semicircle send you a call to ob if the same as the perimeter of the figure is 40 cm find the area of the shaded region

Answer 1

where is the figure dood

Answer 2

Let OA=OB =r. 
Therefore, 40= 22/7* r/2 + 22/7*r + r 
280= 40r 
r=7 
So, shaded area= (1/2*22/7*7/2*7/2 + 1/2*22/7*7*7) 
= 77/4 +77 
= 77 (1/4+1) 
= 77* 5/4 
= 385/4 cm^2 
= 96.25 cm^2