in figure, BOA is a diameter of the circle abd the tangent at a point P meets BA extended at T.if anglePBO=35°, then find anglePTA
70ny:
where's the figure
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join OP then OP=OB [radii]
angl OPB=35
ang AOP=35+35=70[exterior angle property of triangle
join TA
then i quad PTAO
P+T+O+A=360
90+T+90+70=360
ang PTA=360-250
=110
hope my assumptions about the fig is correct
angl OPB=35
ang AOP=35+35=70[exterior angle property of triangle
join TA
then i quad PTAO
P+T+O+A=360
90+T+90+70=360
ang PTA=360-250
=110
hope my assumptions about the fig is correct
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0
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