Question

In figure, line PQ is parallel to BC. AP=5,PB-2,QC-1.8. Find AQ​

Answer 1

Step-by-step explanation:

Here's The Answer.

Check the attachment.

Answer 2

Given:

line PQ is parallel to BC. AP=5 cm, PB=2 cm, and QC=1.8 cm.

Solution:

To find AQ, draw the requires diagram and then apply proportionality theorem,

$\[\Delta ABC \sim \Delta APQ\]$,

$\[\frac{{AB}}{{AP}} = \frac{{AQ}}{{AQ + 1.8}}\]$

$\[ \Rightarrow \frac{{5 + 2}}{5} = \frac{{AQ + 1.8}}{{AQ}}\]$

Cross multiply,

$\[\begin{array}{l} \Rightarrow 7AQ = 5AQ + 9\\ \Rightarrow 2AQ = 9\\ \Rightarrow AQ = 4.5\,{\rm{cm}}\end{array}\]$

Hence, $\[AQ = 4.5{\rm{ cm}}\]$.