Question

in figure PQ is a tangent to a circle with Centre O if Angle B = 30 degree find angle abp and aob

Answer 1

OA=OB (radius)
OAB = OBA ( angles opposite to equal sides are equal)
therefore OBA = 30 degrees
OBP = 90 degrees (tangents connecting radius make 90 degree)
ABP = 60 degrees
AOB = 180 - OBA-OAB
​AOB=120 degrees