Question

In figure PQ is parallel to AB and AQ is parallel to CB. Prove that AR2 = PR.CR

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

By the given explanation, It is proven that PR.CR = AR²  

Given:

In figure PQ is parallel to AB and AQ is parallel to CB  

To find:

Prove that AR² = PR.CR  

Solution:

From the given figure,  

The ΔRBC and ΔRQA are two similar triangles    

Similarly, ΔARB and ΔPRQ are two similar triangles

As we know,

In similar triangles the ratio of corresponding angles is equal  

   

From the ΔRBC and ΔRQA

=> RC/AR = RB/RQ ----- (1)

From the ΔARB and ΔPRQ  

=> AR/PR = RB/RQ ----- (2)

From (1) and (2)

=> RC/AR = AR/PR    

Do cross multiplication

=> PR.CR = AR²    

Therefore,

By the given explanation, It is proven that PR.CR = AR²  

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