in figure tr is perpendicular to ps pq parallel to tr ps is parallel to qr if qr=8cm pq=3cm and sp =12cm find area of (pqrs)
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chaitra4:
plz .i need the answer as soon as possible
do you want the perimeter of pqrs?
I think she is asking for area.
actually its area .. sorry ..i did not see.thag the question is incomplete
that
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Answered by
30
PQRT is a parallelogram
area of Parallelogram PQRT=b×h
=8×3=24cm²
Area of ΔRST=1/2×b×h
=1/2×3×4=12/2
=6cm²
Area of PQRS=24+6=30cm²
area of Parallelogram PQRT=b×h
=8×3=24cm²
Area of ΔRST=1/2×b×h
=1/2×3×4=12/2
=6cm²
Area of PQRS=24+6=30cm²
Answered by
30
ptrq is a parellelogram
area of parellogram= base* height=8*3=24 cm^2
str is a right angled triangle
area of str=1/2*base*height
=1/2*ts*tr
ts=sp-pt
pt=qr=8 cm
ts=12-8=4cm
area of str=1/2*4*3=6cm^2
area of pqrs=area of ptrq+area of str
=24+6=30 cm^2
area of parellogram= base* height=8*3=24 cm^2
str is a right angled triangle
area of str=1/2*base*height
=1/2*ts*tr
ts=sp-pt
pt=qr=8 cm
ts=12-8=4cm
area of str=1/2*4*3=6cm^2
area of pqrs=area of ptrq+area of str
=24+6=30 cm^2
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