In given figure ABCD is quadrilateral in which
BC=3cm AD=13cm D C=12cm and angleABD=angle BCD=
90° Calculate the length of AB
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In the triangle DBC
{db }^{2} = {dc}^{2} + {bc }^{2}
{db}^{2} = {12}^{2} + {3 }^{2} =153.
In triangle DBA
{ad}^{2} = {db}^{2} + {ab}^{2}
{13}^{2} = 153 + {ab}^{2}
{ab}^{2} = 169 - 153 = 16
ab = \sqrt{16} = 4
.'. ab=4cm
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