Question

In given figure,
Angle B = angle C
BP is perpendicular to AC
CQ is perpendicular to AB
Prove that BP = CQ ​

Answer 1

IN TRIANGLE BQC AND BPC

BC = BC (COMMON)

BQ = CP {(AQ=BQ) & (AP=CP)}(PERPENDICULAR)

Angel QBC=Angel PCB

HENCE PROVED...