In given figure , O is the centre of the circle. If abc is 160° find the value of x
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x = 100° hope it helps you
because 160/2=80°
then 80°+x = 180°
x = 100°
because 160/2=80°
then 80°+x = 180°
x = 100°
tejas276:
thnx for your kind help
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hey!
theorems to be known
angle subtended at the centre is twice the angle subtended at remaining part of the circle
NOTE - sum of opposite angles of a cyclic quadrilateral is 180°
1/2<AOC= <ADC
1/2×160°=80° = <ADC
ABCD is a cyclic quadrilateral
<D+<B =180°
<B = 180°-80°
<B=100°
x=100°
theorems to be known
angle subtended at the centre is twice the angle subtended at remaining part of the circle
NOTE - sum of opposite angles of a cyclic quadrilateral is 180°
1/2<AOC= <ADC
1/2×160°=80° = <ADC
ABCD is a cyclic quadrilateral
<D+<B =180°
<B = 180°-80°
<B=100°
x=100°
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