Question

In how many ways can 5 blue balls, 4 white balls and the rest 6 of different colour balls be arranged in a row

Answer 1

Here, all the balls are not different.

Total number of balls= 5 + 4 + 6 = 15

Number of blue balls= 5

Number of white balls= 4

Rest 6 balls are of different colours

From the above given formula, the required number of arrangements

=15!/5!×4!