Question

in how many ways can 5 boys and 3 girls be arrange so that no two girls may sit together

Answer 1

The seating arrangement would be as follows 5 girls can sit in any of 5 places Number of ways they can sit = 5P5 = 5!/( 5 5)! = 5!/0! = 5!/1 = 5 4 3 2 1 = 120 ways Hence total number of ways they can sit = 120 120 = 14400 ways.HENCE THEY HAVE A LOT OF WAYS