Question

in how many ways can the letters of the word assassination be arranged so that the words always start with A and end with N

Answer 1

11!/2!2!3!4!=11×10×.......×4!/2!2!3!4
=11×10×......3/2×2×3×2×1

Answer 2

Answer: There are 415800 ways that the word start with A and end with N.

Step-by-step explanation:

Since we have given that

"Assassination"

We need to arrange the words that always start with A and end with N.

So, place of A and N is fixed.

Since there are 3A, 4S, 2I, T, O, 2N

One A and One N are fixed.

2A's and 1N are still left.

So, number of arrangement would be

$\dfrac{11!}{4!\times 2!\times 2!}\\\\=415800$

Hence, there are 415800 ways that the word start with A and end with N.