in hydrogen atom energy of first excited state os -3.4then find out KE of same orbit of hydrogen. full solution.
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Answer:
kinetic energy is just negative of total energy
potential energy is double of total energy
kinetix energy = 3.4
for explation see two page derivation by bohr bhaiya
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Answer:total energy E = T + V
where
T = kinetic energy and V is potential energy ,
the potential is V= - k. e^2 / r and T = (1/2)m. v^2
however the centripetal force m.v ^2 / r = k.e^2/(r^2)
therefore T =(1/2)m. v^2 = (1/2) .k. e^2 / r = - V/2
so, the magnitude of V = 2.T and is negative in character.
E = -3.4 eV = T -2.T = -T therefore the kinetic energy must be 3.4 ev
I hope it helps uhhh✌✌
where
T = kinetic energy and V is potential energy ,
the potential is V= - k. e^2 / r and T = (1/2)m. v^2
however the centripetal force m.v ^2 / r = k.e^2/(r^2)
therefore T =(1/2)m. v^2 = (1/2) .k. e^2 / r = - V/2
so, the magnitude of V = 2.T and is negative in character.
E = -3.4 eV = T -2.T = -T therefore the kinetic energy must be 3.4 ev
I hope it helps uhhh✌✌
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