In isolation (triangle) ABC, AB=AC=8cm and BC=6cm. If the length of altitude on base is 5cm.,find the length of altitudes on equal sides of triangle.
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AB=8cm.
now area of right triangle = 1/2×base×height
= 1/2.3.5= 7.5cm2
area of isos celes triangle = 7.5×2= 15cm2
again area = 1/2. 4 . x= 15cm2
= 2x= 15
x= 7.5 cm
length of altitude is 7.5 cm
AB=8cm.
now area of right triangle = 1/2×base×height
= 1/2.3.5= 7.5cm2
area of isos celes triangle = 7.5×2= 15cm2
again area = 1/2. 4 . x= 15cm2
= 2x= 15
x= 7.5 cm
length of altitude is 7.5 cm
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