In Michelson’s Interferometer the readings of a pair of maximum distinctness were found to be 0.6939 mm and 0.9884 mm. If mean wavelength of the doublet used is 5893Å, find the difference between wavelengths of components. [5.89 Å]
Answers
The difference between wavelengths of components is 5.896001528 ×10-8 m or 589.6Å
Given:
A pair of maximum distinctness were found to be 0.6939 mm and 0.9884 mm.
The mean wavelength of the doublet used is 5893Å.
To find:
The difference between wavelengths .
Solution:
λ1 - λ2 = λ1 × λ2 / 2x
The difference (λ1 - λ2) is then written as: (λₐᵥ)² / 2x
Substituting the values given in the equation:
Note: Units are converted to meter while calculating.
(5893 × 10⁻¹⁰)² / 2 × ((0.9884 - 0.6939)×10⁻³)
= 3.4727449 × 10-11 / 0.000589
= 5.896001528 ×10-8
Therefore, the difference between the wavelengths is found to be 5.896001528 ×10-8 m or 589.6Å.
#SPJ1
Answer: The difference between wavelengths of components is 5.89 Å.
Given:
- Michelson’s Interferometer the readings of a pair of maximum distinctness were found to be 0.6939 mm and 0.9884 mm.
- Mean wavelength of the doublet used is 5893Å.
To Find: The difference between wavelengths of components.
Explanation: As we know that maximum distinctness were found to be 0.6939 mm and 0.9884 mm i.e and mean or average wavelength of the doublet used is 5893Å.
A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or over a wire.
So, we can say that the difference between wave lengths of components is 5.89 Å.
For more questions follow the link given below
https://brainly.in/question/43731720
https://brainly.in/question/41318102
#SPJ1