Math, asked by sheenasheena533, 1 month ago

Two angles are in the ratio 1: 2. On increasing the smaller angle by 6 and decreasing thelarger angle by 6, the ratio changed to 2:3.What were the original angles ?​

Answers

Answered by Renumahala2601
1

Answer:

Let the two angles be x and 2x

Increasing smaller by 6° and decreasing the larger by 6°, the ratio changes to 2: 3

⇒ 3×(x + 6) = 2×(2x – 6)

⇒ 3x + 18 = 4x – 12

⇒ 4x – 3x = 18 + 12

⇒ x = 30

Original angles are 30° and 2x = 2× 30 = 60°

∴ Original angles are 30° and 60°

Answered by 12thpáìn
39

Given

  • Two angles are in the ratio 1: 2

To find

  • Original angles

Let,

  • Smaller Angle be x
  • Larger angle be 2x

It is given that on increasing the smaller angle by 6 and decreasing the larger angle by 6 then, Ratio Changed to 2:3

According to Question

\\→ \sf \cfrac{x + 6}{2x - 6}  =  \cfrac{2}{3} \\

Cross Multiplying Both side

\\→ \sf 3(x + 6) = 2(2x - 6)

\sf→ 3x + 18 = 4x - 12\\

On transfering 4x to LHS and 18 to RHS

\\\sf→ 3x  - 4x = - 12 - 18

\sf  → - x = -  30

\sf →  x =  30\\

  • The Original angel are 30 and 60.

\\

Verification

 \dfrac{30}{60}  =  \dfrac{1}{2}

\dfrac{1}{2}  =  \dfrac{1}{2}

Verified

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