Question

in Millikan's oil drop experiment a charged particle of mass 'm' is in equilibrium in an applied electric field the
direction of electric field is reversed then acceleration of the particle will be​

Answer 1

Answer:

We assume the oil droplet’s charge is a positive charge q and the field E is pointing up to hold the charge against gravity. The actual experiment for an electron has E pointing down for a negative electron charge but that doesn’t matter for our argument below because if q is inverted and E is inverted the force has the same direction.

The oil droplet starts with a suspended state where the net force is:

f=qE−mg=0 thus qE=mg

If E is suddenly inverted then the initial acceleration before friction with the air becomes a limiting factor is:

f=−qE−mg=−2mg thus the initial acceleration is 2g .

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