Biology, asked by nirurocky2853, 27 days ago

“In our body nerve impulses are generated and conducted by active transport

of ions”. Justify the statement with suitable explanation.​

Answers

Answered by Sweetoldsoul
66

Answer:

TRANSMISSION OF NERVE IMPULSE

  • Normal State/ Polarized State

In the normal (resting) condition, the outer side of the nerve fiber carries positive (+) charge. This is called polarized state. At this state more Na+ ions are outside the the axon membrane.

  • On Stimulation (Depolarized State),

The axon membrane at the spot where stimulation takes place becomes more permeable to Na+ which move inwards and cause loss of Polarization, i.e., they become excited (depolarized state).

  • Repolarization

Meanwhile, the previous region become Repolarized due to active transport of Na+ ions again to the outside. (This transport is achieved by using energy thru ATP and its called ‘‘Sodium Pump’’).

‘‘Conduction of nerve impulse is a wave of depolarization followed by repolarization’’

Which means conduction of nerve impulse takes place by the movement of Na+ ions in and out of the axon membrane. While depolarization, Na+ ions move inside the membrane, and during repolarization they move outside the membrane due to the active transport of Na+ ions using energy thru ATP.

                             

Hope this helps!

[In the attachment, ignore the movement of K+ ions for now, they move opposite to Na+ ions, that is, if Na+ ions move out they move in and vice Versa]

Attachments:
Answered by ummhabibamattihalli
18

Answer:

Which means conduction of nerve impulse takes place by the movement of Na+ ions in and out of the axon membrane. While depolarization, Na+ ions move inside the membrane, and during repolarization they move outside the membrane due to the active transport of Na+ ions using energy thru ATP.

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