“In our body nerve impulses are generated and conducted by active transport
of ions”. Justify the statement with suitable explanation.
Answers
Answer:
TRANSMISSION OF NERVE IMPULSE
- Normal State/ Polarized State
In the normal (resting) condition, the outer side of the nerve fiber carries positive (+) charge. This is called polarized state. At this state more Na+ ions are outside the the axon membrane.
- On Stimulation (Depolarized State),
The axon membrane at the spot where stimulation takes place becomes more permeable to Na+ which move inwards and cause loss of Polarization, i.e., they become excited (depolarized state).
- Repolarization
Meanwhile, the previous region become Repolarized due to active transport of Na+ ions again to the outside. (This transport is achieved by using energy thru ATP and its called ‘‘Sodium Pump’’).
‘‘Conduction of nerve impulse is a wave of depolarization followed by repolarization’’
Which means conduction of nerve impulse takes place by the movement of Na+ ions in and out of the axon membrane. While depolarization, Na+ ions move inside the membrane, and during repolarization they move outside the membrane due to the active transport of Na+ ions using energy thru ATP.
Hope this helps!
[In the attachment, ignore the movement of K+ ions for now, they move opposite to Na+ ions, that is, if Na+ ions move out they move in and vice Versa]
Answer:
Which means conduction of nerve impulse takes place by the movement of Na+ ions in and out of the axon membrane. While depolarization, Na+ ions move inside the membrane, and during repolarization they move outside the membrane due to the active transport of Na+ ions using energy thru ATP.