In parallelogram ABCD, E and F are any two points on the side AB and BC respectively. Show that ar( △ADF)=ar( △DCE) (hint- draw EG| |AD, FH| |AB)
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Ans. In ABC, points D and E divides BC in three equal parts such that BD = DE = EC.
BD = DE = EC =  BC
Draw AFBC
ar (ABC) =  ……….(i)
and ar (ABD) = ……….(ii)
=  = 
=  ar (ABC) ……….(iii)
And ar (AEC) =  ar (ABC) ……….(iv)
From (ii), (iii) and (iv),
ar (ABD) = ar (ADE) = ar (AEC)
HOPE SO THIS HELP U
BD = DE = EC =  BC
Draw AFBC
ar (ABC) =  ……….(i)
and ar (ABD) = ……….(ii)
=  = 
=  ar (ABC) ……….(iii)
And ar (AEC) =  ar (ABC) ……….(iv)
From (ii), (iii) and (iv),
ar (ABD) = ar (ADE) = ar (AEC)
HOPE SO THIS HELP U
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