In parallelogram ABCD , the measure of angleA exeeds thrice the measure of angleB by 20° . Find the measures of angle A and angleB .
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let angle b be x. therefore angle a is 3x+20.
x +3x+20=180
4x=180-20
x=160÷4
x=40
angle a is 140 deg.
angle b is 40 deg.
x +3x+20=180
4x=180-20
x=160÷4
x=40
angle a is 140 deg.
angle b is 40 deg.
geetakhadka:
angle A = 140° and angleB = 40°.
sorry i had not seen the word twice
it is thrice not twice
plzzz solve and give
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