in parallelogram EFGH, angle H = 60° bisectors of E and H meet at O. find measure of EOH
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Answered by
1
Answer:
Let ∠A be 2x
Let ∠D be 2y
Since AB∥DC , sum of angles on same side of the transversal AD will be 180
o
=>2x+2y=180
o
x+y=90
o
After bisection of angles A and D, we get ∠1=x and ∠2=y as per the given figure.
Now in △AOD, we have
x+y+∠AOD=180
o
90
o
+∠AOD=180
o
=>∠AOD=90
o
Answered by
0
Answer: ok
Step-by-step explanation: he is wrong guys
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