Question

in parallelogram EFGH, angle H = 60° bisectors of E and H meet at O. find measure of EOH​

Answer 1

Answer:

Let ∠A be 2x

Let ∠D be 2y

Since AB∥DC , sum of angles on same side of the transversal AD will be 180

o

=>2x+2y=180

o

x+y=90

o

After bisection of angles A and D, we get ∠1=x and ∠2=y as per the given figure.

Now in △AOD, we have

x+y+∠AOD=180

o

90

o

+∠AOD=180

o

=>∠AOD=90

o

Answer 2

Answer: ok

Step-by-step explanation: he is wrong guys