in physics dimensional equation is x= at+bv²+c find dimension of a,b and c whereas x= position,v= speed and t= time
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since dimensions of same quantity can not be added.therefore
x=at , x=bv² , x=c
a=x/t = [LT⁻¹]
b= x/v² = [L⁻¹T⁴]
c= x = [L]
x=at , x=bv² , x=c
a=x/t = [LT⁻¹]
b= x/v² = [L⁻¹T⁴]
c= x = [L]
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1
x=at
x/t = a
a = [L]/[T]
x = bv2
[L] = b [L^2T^-2]
B= [L^-1T^-2]
x = c
[L] = c
x/t = a
a = [L]/[T]
x = bv2
[L] = b [L^2T^-2]
B= [L^-1T^-2]
x = c
[L] = c
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