Biology, asked by divyanshtripathi1feb, 8 months ago

In plant cell, placed in ____(1)____ solution, water escapes from the vacuoles of the cell by ____(2)____. The cell becomes ____(3)____. The process of shrinkage of cytoplasm along with the ____(4)____, from the cell wall is called ____(5)____.

Answers

Answered by myrakincsem
0

In plant cell, placed in hypertonic solution, water escapes from the vacuoles of the cell by exosmosis. The cell becomes flaccid. The process of shrinkage of cytoplasm along with the vacuole, from the cell wall is called plasmolysis.

Explanation:

  • When a cell is placed in a hypertonic solution, the concentration of water is more inside the cell as compared to the outside of a cell.

  • As a result, the plant cell will release water into the solution through the process of osmosis.

  • When excess water will lose from the cell, we say the that the cell has become flaccid.

  • The vacuole which stores water also shrinks.

  • This phenomenon is termed as plasmolysis.
Answered by Anonymous
0

Answer:

In plant cell, placed in hypertonic solution, water escapes from the vacuoles of the cell by exosmosis. The cell becomes flaccid. The process of shrinkage of cytoplasm along with the vacuole, from the cell wall is called plasmolysis.

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