In ∆pqr, ps bisects angle pqr, if p =z, qr = z+10,ps=z-4, sr=z+4, find the value of z
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Answer:
In ∆ABC,
∠ACD = ∠A + ∠B (Exterior angle property)
= 70∘ + 40∘
= 110∘
Hence, the measure of ∠ACD is 110∘.
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