In ∆PQR, seg PM is a median,PM=9 and PQ²+PR²=290.find the length of QR.
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Answer:
PQ2+PR2=2PM2+QM2+RM2
290= 2X81+ 2 QM2. (QM=RM)
290-152=2QM2
128/2= QM2
QM=8
QR= QM+MR=8+8=16
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