Question

In PQR such that angle P=50 degree and Q =60 degree and PQ =6.1 and construct its circumcircle.​

Answer 1

Answer:

hope you will help for this answer.

Answer 2

Given : P=50 degree and Q =60 degree and PQ =6.1

To Find : Construct triangle and its circum circle

Solution:

Step 1 :  Draw a line segment PQ = 6.1  cm

Step 2 : Draw an angle of 50° at P on PQ  using protractor and draw ray PX

Step 3 : Draw an angle of 60° at Q on PQ  using protractor and draw ray QY

Step 4 : ray PX and QY intersects at R

ΔPQR is constructed

Step 5 : Draw perpendicular bisector of  PR

Step 6 :  Draw perpendicular bisector of  QR

Step 7 : perpendicular bisector intersects at O

Step 8 :  Using compass width = OP = OQ = OR  and taking O as center draw circle.

Perpendicular bisector of PR :

Using suitable compass width and taking P as center draw arcs on both sides.

Keeping compass width same and taking R as center draw arcs on both sides such that it intersects arc drawn in previous step at M & N

Draw  a line passing through M and N

Similarly draw Perpendicular bisector of QR :

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