Question

in quadratic equation 3x² - 5x - 7 =0, b =​

Answer 1

Given, 3x^2 + 5x + 7 = 0

Put x = 0 in above equation :

0 + 0 + 7 = 0 (which is not possible)

Put x = 1 in above equation :

3 + 5 + 7 = 0 (which is not possible)

Put x = 2 in above equation :

12 + 10 + 7 = 0 (which is not possible)

From above equations we can conclude that for any value for x > 2, 3x^2 will always be positive and will be greater than 5x.

So it's not possible for any positive value of x.

As (positive) +(positive) +(positive) cannot be zero.

Now, check for negative values.

As we know 3x^2 will always be positive and (3x^2 + 7) will always be greatest than 5x for any value of x. So,

{(3x^2 + 2) - 5x } > 0

So no such real values of x exists which can satisfy the given equation.