In quadrilateral abcd if diagonal ac bisects angle a and ab is equal to ad then show taht angle cbo is equla to angle cdo
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Answer:
Step-by-step explanation:
Given that diagonal AC bisects angle A
=>∠DAO = ∠BAO
Also given that AB = AD
Now Consider triangles ABC and ADC, we have
AB = AD (given)
∠DAC = ∠BAC (given)
AC = AC (common side)
Henceby S-A-S axiom , both triangle are congruent,
=> BC = CD.-----(*)
Also ∠DCO = ∠BCO.-----(**)
Now consider triangle DOC and BOC,
DC = BC (from *)
∠DCO = ∠BCO (from **)
OC = OC (common side)
=> Both the triangles ODC and OBC are congruent as per S-A-S axiom
Hence, ∠CDO = ∠CBO ( Angles opposite to common side)
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