In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?
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In △ABC and △ABD,
AC=AD (Given)
∠CAB=∠DAB (AB bisects ∠A)
AB=AB (Common)
∴△ABC≅△ABD (By SAS congruence rule)
∴BC=BD (By CPCT)
∴, BC and BD are of equal lengths.
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