In quadrilateral, If angle A is twice angle B, angle C = angle D = (x +50)degree, Then find the each of the angles?
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Step-by-step explanation:
A.T.Q.
2x+x+(x+50)+(x+50)=360 degrees (Angle Summ Property of Quadrilateral)
5x+100=360
5x=360-100
5x=260
x=260/5
x=52
Ange A = 52*2 = 104 degrees
Angle B=52 degrees
Angle C=52+50=102 degrees
Angle D=52+50=102degrees
Verification:
=104+52+102+102
=360 degrees
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