In rectangle ABCD,AB=x+y,BC=x-y,CD=9,AD=3 find the value of x&y
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hey mate
here is your answer
as ABCD is a rectangle ,
opposite sides of ABCD are equal
AB=CD
BC=AD
AB=x+y=9 .........i
BC=x-y =3............ii
add i and ii
x+y=9
+x-y=3
2x=12
x=6
put the value of x in i
x+y=9
6+y=9
y=3
values of x and y are 6 and 3 respectively
hope it helps
here is your answer
as ABCD is a rectangle ,
opposite sides of ABCD are equal
AB=CD
BC=AD
AB=x+y=9 .........i
BC=x-y =3............ii
add i and ii
x+y=9
+x-y=3
2x=12
x=6
put the value of x in i
x+y=9
6+y=9
y=3
values of x and y are 6 and 3 respectively
hope it helps
aadi4853:
hello my dear friend
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