Question

in rhombus ABCD AB=4 then what is AC square +BD square

Answer 1

The given figure is a rhombus so all its sides are equal i.e 4cm

So, AC and BD are of 4cm

Now,

AC^2 + BD^2

4^2+4^2

16+16

32 ...

Hence, Proved.

Answer 2

Step-by-step explanation:

AC^2 + BD^2 = 16 cm

we have to solve this by using Pythagoras theorem