In right angle triangle ABC 8 cm 15 cm and 17 cm are the lengths of AB, BC and CA respectively. Then find out Sin A, Cos A and Tan A ?
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Answered by
120
Hey mate !!
Here's the answer !!
Refer to the attachment for the diagram !!
According to the question,
AB = 8 cm, BC = 15 cm, AC = 17 cm
According to the diagram,
AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.
Now we need to find Sin A, Cos A, and Tan A.
Let us calculate Sin A first,
Sin A = Opposite / Hypotenuse
=> Sin A = BC / AC
=> Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
=> Cos A = AB / AC
=> Cos A = 8 / 17
Tan A = Opposite / Adjacent
=> Tan A = BC / AB
=> Tan A = 15 / 8
Hope my answer helps !!
Cheers !!
Here's the answer !!
Refer to the attachment for the diagram !!
According to the question,
AB = 8 cm, BC = 15 cm, AC = 17 cm
According to the diagram,
AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.
Now we need to find Sin A, Cos A, and Tan A.
Let us calculate Sin A first,
Sin A = Opposite / Hypotenuse
=> Sin A = BC / AC
=> Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
=> Cos A = AB / AC
=> Cos A = 8 / 17
Tan A = Opposite / Adjacent
=> Tan A = BC / AB
=> Tan A = 15 / 8
Hope my answer helps !!
Cheers !!
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