Question

In square PQRS :(ii) of PR =5x and QS =9x-8. Find QS .


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Answer 1

Note:

We know that In a square all sides are equal in length.

Given, PR = 5x and QS = 9x - 8.

⇒ 5x = 9x - 8

⇒ -4x = -8

⇒ x = 2.

Now,

⇒ QS = 9(2) - 8

          = 10.

Therefore, QS = 10.

Hope it helps!

Answer 2

PR=5x Q's=9x -8=x,5x + x =5x'2