Question

in sulfur estimation 0.157g of organic compound gave 0.4813g of BaSO4.Calculate the percent of sulfur in the compound

Answer 1

Answer:

42.10%

Explanation:

Here, mass of the substance taken= 0.157g

Mass of BaSO4 ppt. formed= 0.4813g

1 mole of BaSO4 is equivalent to 1 g atom of S

(137+32+64)= 233g of BaSO4=32g of S

0.4813g of BaSO4 will contain sulphur= (32/233) x 0.4813

% of sulphur in the compound= (32/233) x(0.4813)x(100/0.157)

= 42.10

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Answer 2

Answer:Ithink it is 42.10%

Hope it will help

Explanation: