Question

In the ∆ABC, DE || BC. If AB : AD = 5 : 3 then area of ∆ABC : area of ∆ADE is​

Answer 1

$\sf \pink{AB/AD=5/3}$

$\sf \pink{ar(△ABC/ar(△ADE)}$

=$\sf \pink{(AB/AD)^2}$}[/tex]

=$\sf \pink{5^2/3^2}$

$\sf \pink{R2=25:9}$

Answer 2

$\huge\fbox\pink{✯Answer✯}$

$\huge\boxed{\fcolorbox{purple}{ink}{GIVEN:}}$

AB : AD = 5 : 3

$\huge\boxed{\fcolorbox{red}{ink}{SOLUTION:}}$

$\frac{AB}{AD} = \frac{5}{3}$

$\sf \red{AB/AD=5/3} \\\sf \green{ar(△ABC/ar(△ADE)}$

$= \sf \purple{(AB/AD)^2}$ =$\sf \green{5^2/3^2}$

$\sf \blue{R2=25:9}$