in the adjacent figure AC =ae ,ab= ad and angle BAD = angle BAC show that BC= DE
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racha11:
yah
lol these cannot be equal..
the same problem
there is mistake in this question
maybe
if so i will find answer i will send you
Okay. But it cannot be possible. Angle BAD canbe equal to angle BAC only in the case when BD=DC
BD=BC *
angle BAD = angle EAC... it is shown in figure... its a typing mistake.
which class is it ? do you know trigonometry ? or is it just pure geometry qn ?
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17
It is simple. When we find some sides and angles are equal, then think of similar and congruent triangles....
Compare ΔABC and ΔADE:
AB = AD, AC = AE
and ∠BAC = ∠BAD + ∠DAC
. = ∠EAC + ∠CAD = ∠EAD
So by SAS criterion, the two triangles are congruent.
So BC = DE.
Compare ΔABC and ΔADE:
AB = AD, AC = AE
and ∠BAC = ∠BAD + ∠DAC
. = ∠EAC + ∠CAD = ∠EAD
So by SAS criterion, the two triangles are congruent.
So BC = DE.
hope it's easy to follow.
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