In the adjacent figure AE = BE And angle C = angle D . Prove that BD = AC.
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Step-by-step explanation:
We have AE=AD and CE=BD.
Adding, we get AE+CE=AD+BD
⇒AC=AB.
In triangles AEB and ADC, we have
AE=AD ___(given);
AB=AC ___ (proved);
∠EAB=∠DAC, (common angle).
By SAS postulate △AEB≅△ADC.
Hope it's helpful to you
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