Math, asked by nano101, 1 year ago

In the adjacent figure,the bisectors of ∠A and ∠B meet in a point p. If ∠C = 100° and ∠D = 60° , find the measure of ∠APB. please solve this.

Attachments:

tinkertweet: Is ABCD a quadilateral?
nano101: yes
nneehhaa66: obio

Answers

Answered by nneehhaa66
302
In quadrilateral ABCD, AP and BP are the biscetors of A and B then APB=1/2 C+D.Itz a theorem

Therefore, 100+60÷2=80


nano101: but the answer is 80°, it's given in my textbook.
nneehhaa66: let me check
nneehhaa66: Whch txtbook do u hve???
nano101: rs aggarwal
nneehhaa66: oh kk
nano101: thanks alot!
nneehhaa66: plzzzz mark my answer as the best one......c ma answer hve been rated
Answered by tinkertweet
877

In quadilateral ABCD,LET angle PAB=PAD=x,angle PBA=PBC=y;

angle A+angle B+angle C+angle D=360

angle PAD +angle PAB +angle PBA +angle PBC+angle C+angle D=360

x+x+y+y+100+60=360

2(x+y)+160=360

2(x+y)=360-160

2(x+y)=200

x+y=200/2

x+y=100

Now in triangle PAB;

angle PAB+angle PBA+angle APB=180

x+y+ angle P=180

100+angle P=180 (Since x+y=100)

angle P=180-100

angle P=80

Hope I Helped!

Please mark this as the best answer


nano101: how is PAB=PAD and PBA=PBC?
tinkertweet: because the question says that the bisectors of angle A and angle B meet at P
tinkertweet: thus angle A is bisected to angles PAB AND PAD while angle B is bisected to angles PBA and PBC
nano101: oh ok! thanks!
tinkertweet: your welcome......pls mark this as thebest answer
tinkertweet: thanks so much!!
nano101: do you know the answer to this question? http://brainly.in/question/83637
tinkertweet: Its already answered
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