In the adjacent figure,the bisectors of ∠A and ∠B meet in a point p. If ∠C = 100° and ∠D = 60° , find the measure of ∠APB. please solve this.
Attachments:
tinkertweet:
Is ABCD a quadilateral?
Answers
Answered by
302
In quadrilateral ABCD, AP and BP are the biscetors of A and B then APB=1/2 C+D.Itz a theorem
Therefore, 100+60÷2=80
Therefore, 100+60÷2=80
Answered by
877
In quadilateral ABCD,LET angle PAB=PAD=x,angle PBA=PBC=y;
angle A+angle B+angle C+angle D=360
angle PAD +angle PAB +angle PBA +angle PBC+angle C+angle D=360
x+x+y+y+100+60=360
2(x+y)+160=360
2(x+y)=360-160
2(x+y)=200
x+y=200/2
x+y=100
Now in triangle PAB;
angle PAB+angle PBA+angle APB=180
x+y+ angle P=180
100+angle P=180 (Since x+y=100)
angle P=180-100
angle P=80
Hope I Helped!
Please mark this as the best answer
Similar questions