In the adjacent figure ZA = 50°. If BD and CD are angle bisectors of ZABC and ZACB respectively, find the measure of ZBDC.
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Answer:
115
Explanation:
Let b be ZDBC and c be ZDCB.
Because DB is an angle bisector, ZABC is 2b
Because DC is an angle bisection, ZACB is 2c
2b + 2c = 180- 50 = 130
b + c = 65
All internal angles of triangle DBC is 180
ZBDC is 180 - (b +c) = 180- 65 = 115
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