Question

In the adjoining circuit, the reading of the ammeter is​

Answer 1

Answer:

The reading is 4A.

Explanation:

R=1/4+1/2+2

=1/4+1/4

=1+1/4

=2/4

R=0.5ohms.

V=IR

I=V/R

I=2/0.5

I=4A.

Answer 2

Reading of ammeter in the adjoining circuit:

Solution:

Total resistance = 4+2+2= 8 ohms

We know that  

The formula for ohm law to find voltage is  

V=IR

By putting values in the above equation we get

2V= I* 8Ohms

2/8= I

0.25= I

So the reading of ammeter in the adjoining circuit is o.25.

Hope it helped...