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In the adjoining figure, ABCD is a square of side 28 cm. Find the area of
shaded region
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Answer:
A(Sector 1)=Theta/360×πr^2
=90/360×22/7×14×14
=22/4×2×14
=22×7
=154 sq.cm
Similarly,
A(Sector 2)=A(Sector 3)=A(Sector 4)=154 sq.cm
Therefore, A(Sectors)=A(sec 1)+A(sec 2)+A(sec 3)+A(sec 4)=616 sq.cm
A(■ABCD)= Side^2
=28×28
=784 sq.cm
A(Shaded region)=A(■ABCD)-A(Sectors)
=784-616
=168 sq.cm
Area of the shaded region is 168 sq.cm
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